A metal coin is at the bottom of a beaker filled with a liquid of refractive index 4/3 to height of 6 cm. To an observer looking from above the surface of the liquid, coin will appear at a depth of :
Text Solution
Verified by ExpertsThe correct answer is:
C
Here : Actual depth of liquid h = 6 cm, Refractive index of the liquid = 
Using the relation
μ = 
μ =
or x = h × 
= 6 × 
= 4.5 cm
Hence, the coin will appear at a depth of
= 6 – 4.5 = 1.5 cm
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A disc is placed on a surface of pond which has refractive index 5/3. A source of light is placed 4…
A light wave has a frequency of and a wavelength of in a medium. The refractive index of the medi…
How much water should be filled in container 21 cm in height, so that it appears half filled when v…
Monochromatic light is refracted from air into glass of refractive index µ. The ratio of the wavele…
For a colour of light the wavelength for air is 6000 A and in water the wavelength is 4500 A. Then …
On heating a liquid the refractive index generally: